3. (B) Program for Newton’s backward interpolation.

3. (B) Program for Newton’s backward interpolation.

clc;clear;close
x=[15 20 25 30 35 40];
y=[0.2588190 0.3420201 0.4226183 0.5 0.5735764 0.6427876];
h=5
c=1;
for i=1:5
d1(c)=y(i+1)-y(i);
c=c+1;
end
c=1;
for i=1:4
d2(c)=d1(i+1)-d1(i);
c=c+1
end
c=1;
for i=1:3
d3(c)=d2(i+1)-d2(i);
c=c+1;
end
c=1;
for i=1:2
d4(c)=d3(i+1)-d3(i);
c=c+1;
end
c=1;
for i=1:1
d5(c)=d4(i+1)-d4(i);
c=c+1 ;
end
d=[d1(5) d2(4) d3(3) d2(2) d1(1)];
x0=38;
pp=1;
y_x=y(6);
p=(x0-x(6))/h;
for i=1:5
pp=1;
for j=1:i
pp=pp*(p-(j-1))
end
y_x=y_x+(pp*d(i))/factorial(i);
end
printf('value of function at %f is:%f',x0,y_x);
3. (B) Program for Newton’s backward interpolation. 3. (B) Program for Newton’s backward interpolation. Reviewed by admin on December 24, 2019 Rating: 5

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